A projectile is fired from level ground at an angle $\theta $ above the horizontal. The elevation angle $\phi $ of the highest point as seen from the launch point is related to $\theta $ by the relation
A projectile is fired from level ground at an angle $\theta $ above the horizontal. The elevation angle $\phi $ of the highest point as seen from the launch point is related to $\theta $ by the relation
- A
$\tan \,\phi = \frac{1}{4}\,\tan \,\theta $
- B
$\tan \,\phi = \tan \,\theta $
- C
$\tan \,\phi = \frac{1}{2}\,\tan \,\theta $
- D
$\tan \,\phi = 2\,\tan \,\theta $
Similar Questions
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A projectile is projected with velocity of $25\, m / s$ at an angle $\theta$ with the horizontal. After t seconds its inclination with horizontal becomes zero. If $R$ represents horizontal range of the projectile, the value of $\theta$ will be : [use $g =10 m / s ^{2}$ ]
- [JEE MAIN 2022]
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- [AIIMS 2001]
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